Base | Representation |
---|---|
bin | 10011100000000110100… |
… | …101010110001110010000 |
3 | 11202010010200022102120002 |
4 | 103200012211112032100 |
5 | 133424101401000000 |
6 | 2503352452305132 |
7 | 165551632113326 |
oct | 23400645261620 |
9 | 4663120272502 |
10 | 1340140250000 |
11 | 477394263122 |
12 | 19788a3121a8 |
13 | 994b4243a66 |
14 | 48c12623d16 |
15 | 24cd7db28d5 |
hex | 13806956390 |
1340140250000 has 70 divisors (see below), whose sum is σ = 3245611229082. Its totient is φ = 536056000000.
The previous prime is 1340140249997. The next prime is 1340140250051. The reversal of 1340140250000 is 520410431.
It can be written as a sum of positive squares in 7 ways, for example, as 1279875891856 + 60264358144 = 1131316^2 + 245488^2 .
It is a super-3 number, since 3×13401402500003 (a number of 37 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a polite number, since it can be written in 13 ways as a sum of consecutive naturals, for example, 2430281 + ... + 2930280.
Almost surely, 21340140250000 is an apocalyptic number.
1340140250000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1340140250000 is an abundant number, since it is smaller than the sum of its proper divisors (1905470979082).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1340140250000 is an frugal number, since it uses more digits than its factorization.
1340140250000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5360599 (or 5360568 counting only the distinct ones).
The product of its (nonzero) digits is 480, while the sum is 20.
Adding to 1340140250000 its reverse (520410431), we get a palindrome (1340660660431).
The spelling of 1340140250000 in words is "one trillion, three hundred forty billion, one hundred forty million, two hundred fifty thousand".
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