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13401403224000 = 263531150762891
BaseRepresentation
bin1100001100000100000111…
…1000001110111111000000
31202110011100211111001201120
43003001001320032333000
53224032033211132000
644300304124432240
72552135156613441
oct303010170167700
952404324431646
1013401403224000
1142a7559823050
1216053469a8680
13762992c337cc
143448ba6d92c8
151839043606a0
hexc3041e0efc0

13401403224000 has 224 divisors, whose sum is σ = 48274291982592. Its totient is φ = 3248824960000.

The previous prime is 13401403223987. The next prime is 13401403224061. The reversal of 13401403224000 is 42230410431.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 25117446 + ... + 25645445.

Almost surely, 213401403224000 is an apocalyptic number.

13401403224000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13401403224000 is an abundant number, since it is smaller than the sum of its proper divisors (34872888758592).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13401403224000 is a wasteful number, since it uses less digits than its factorization.

13401403224000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50762932 (or 50762912 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 13401403224000 its reverse (42230410431), we get a palindrome (13443633634431).

It can be divided in two parts, 13401 and 403224000, that added together give a triangular number (403237401 = T28398).

The spelling of 13401403224000 in words is "thirteen trillion, four hundred one billion, four hundred three million, two hundred twenty-four thousand".