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13401414330410 = 251340141433041
BaseRepresentation
bin1100001100000100001010…
…0010100110100000101010
31202110011101121101022212002
43003001002202212200222
53224032044032033120
644300305202451002
72552135353201601
oct303010242464052
952404347338762
1013401414330410
1142a75650194a7
12160534a663a62
13762995321b52
143448bbd8aa38
15183905306375
hexc30428a682a

13401414330410 has 8 divisors (see below), whose sum is σ = 24122545794756. Its totient is φ = 5360565732160.

The previous prime is 13401414330397. The next prime is 13401414330413. The reversal of 13401414330410 is 1403341410431.

It can be written as a sum of positive squares in 2 ways, for example, as 11322975991369 + 2078438339041 = 3364963^2 + 1441679^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13401414330413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 670070716511 + ... + 670070716530.

Almost surely, 213401414330410 is an apocalyptic number.

13401414330410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13401414330410 is a deficient number, since it is larger than the sum of its proper divisors (10721131464346).

13401414330410 is a wasteful number, since it uses less digits than its factorization.

13401414330410 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1340141433048.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 13401414330410 its reverse (1403341410431), we get a palindrome (14804755740841).

The spelling of 13401414330410 in words is "thirteen trillion, four hundred one billion, four hundred fourteen million, three hundred thirty thousand, four hundred ten".

Divisors: 1 2 5 10 1340141433041 2680282866082 6700707165205 13401414330410