13401443000111 has 4 divisors (see below), whose sum is σ = 14106782105400. Its totient is φ = 12696103894824.

The previous prime is 13401443000069. The next prime is 13401443000159. The reversal of 13401443000111 is 11100034410431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13401443000111 - 2³⁸ = 13126565093167 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13401443000411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 352669552616 + ... + 352669552653.

It is an arithmetic number, because the mean of its divisors is an integer number (3526695526350).

Almost surely, 2^{13401443000111} is an apocalyptic number.

13401443000111 is a deficient number, since it is larger than the sum of its proper divisors (705339105289).

13401443000111 is an equidigital number, since it uses as much as digits as its factorization.

13401443000111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 705339105288.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 13401443000111 its reverse (11100034410431), we get a palindrome (24501477410542).

The spelling of 13401443000111 in words is "thirteen trillion, four hundred one billion, four hundred forty-three million, one hundred eleven", and thus it is an aban number.