13401443000411 has 2 divisors, whose sum is σ = 13401443000412. Its totient is φ = 13401443000410.

The previous prime is 13401443000291. The next prime is 13401443000419. The reversal of 13401443000411 is 11400034410431.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13401443000411 - 2³⁴ = 13384263131227 is a prime.

It is a super-2 number, since 2×13401443000411² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13401443000419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700721500205 + 6700721500206.

It is an arithmetic number, because the mean of its divisors is an integer number (6700721500206).

Almost surely, 2^{13401443000411} is an apocalyptic number.

13401443000411 is a deficient number, since it is larger than the sum of its proper divisors (1).

13401443000411 is an equidigital number, since it uses as much as digits as its factorization.

13401443000411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 13401443000411 its reverse (11400034410431), we get a palindrome (24801477410842).

The spelling of 13401443000411 in words is "thirteen trillion, four hundred one billion, four hundred forty-three million, four hundred eleven", and thus it is an aban number.