13401443000112 has 40 divisors (see below), whose sum is σ = 34731714051840. Its totient is φ = 4452783842880.

The previous prime is 13401443000069. The next prime is 13401443000159. The reversal of 13401443000112 is 21100034410431.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 448854412 + ... + 448884267.

It is an arithmetic number, because the mean of its divisors is an integer number (868292851296).

Almost surely, 2^{13401443000112} is an apocalyptic number.

13401443000112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13401443000112 is an abundant number, since it is smaller than the sum of its proper divisors (21330271051728).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13401443000112 is a wasteful number, since it uses less digits than its factorization.

13401443000112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 897739001 (or 897738995 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 13401443000112 its reverse (21100034410431), we get a palindrome (34501477410543).

The spelling of 13401443000112 in words is "thirteen trillion, four hundred one billion, four hundred forty-three million, one hundred twelve", and thus it is an aban number.