134014540433 has 2 divisors, whose sum is σ = 134014540434. Its totient is φ = 134014540432.

The previous prime is 134014540391. The next prime is 134014540453. The reversal of 134014540433 is 334045410431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130557923584 + 3456616849 = 361328^2 + 58793^2 .

It is a cyclic number.

It is not a de Polignac number, because 134014540433 - 2²⁴ = 133997763217 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 134014540433.

It is not a weakly prime, because it can be changed into another prime (134014540453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67007270216 + 67007270217.

It is an arithmetic number, because the mean of its divisors is an integer number (67007270217).

Almost surely, 2^134014540433 is an apocalyptic number.

It is an amenable number.

134014540433 is a deficient number, since it is larger than the sum of its proper divisors (1).

134014540433 is an equidigital number, since it uses as much as digits as its factorization.

134014540433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34560, while the sum is 32.

Adding to 134014540433 its reverse (334045410431), we get a palindrome (468059950864).

The spelling of 134014540433 in words is "one hundred thirty-four billion, fourteen million, five hundred forty thousand, four hundred thirty-three".