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134015207 is a prime number
BaseRepresentation
bin1111111110011…
…10100011100111
3100100011200022012
413333032203213
5233301441312
621144224435
73215052614
oct777164347
9310150265
10134015207
1169714677
1238a6b11b
13219c3251
1413b2750b
15bb73322
hex7fce8e7

134015207 has 2 divisors, whose sum is σ = 134015208. Its totient is φ = 134015206.

The previous prime is 134015171. The next prime is 134015213. The reversal of 134015207 is 702510431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 134015207 - 218 = 133753063 is a prime.

It is a Chen prime.

It is a nialpdrome in base 15.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134015107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67007603 + 67007604.

It is an arithmetic number, because the mean of its divisors is an integer number (67007604).

Almost surely, 2134015207 is an apocalyptic number.

134015207 is a deficient number, since it is larger than the sum of its proper divisors (1).

134015207 is an equidigital number, since it uses as much as digits as its factorization.

134015207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 840, while the sum is 23.

The square root of 134015207 is about 11576.4937265132. The cubic root of 134015207 is about 511.7423515997.

Adding to 134015207 its reverse (702510431), we get a palindrome (836525638).

The spelling of 134015207 in words is "one hundred thirty-four million, fifteen thousand, two hundred seven".