13401770111400 has 192 divisors, whose sum is σ = 45420248632320. Its totient is φ = 3241896134400.

The previous prime is 13401770111377. The next prime is 13401770111417. The reversal of 13401770111400 is 411107710431.

13401770111400 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 862959 + ... + 5248641.

It is an arithmetic number, because the mean of its divisors is an integer number (236563794960).

Almost surely, 2^{13401770111400} is an apocalyptic number.

13401770111400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13401770111400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22710124316160).

13401770111400 is an abundant number, since it is smaller than the sum of its proper divisors (32018478520920).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13401770111400 is a wasteful number, since it uses less digits than its factorization.

13401770111400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4386176 (or 4386167 counting only the distinct ones).

The product of its (nonzero) digits is 2352, while the sum is 30.

Adding to 13401770111400 its reverse (411107710431), we get a palindrome (13812877821831).

The spelling of 13401770111400 in words is "thirteen trillion, four hundred one billion, seven hundred seventy million, one hundred eleven thousand, four hundred".