Base | Representation |
---|---|
bin | 111110011010000100… |
… | …1001111111000101111 |
3 | 110210221000001202011220 |
4 | 1330310021033320233 |
5 | 4143432304411100 |
6 | 141322320314423 |
7 | 12453053136402 |
oct | 1746411177057 |
9 | 423830052156 |
10 | 134018825775 |
11 | 5192315144a |
12 | 21b82772a13 |
13 | c83a688053 |
14 | 66b511dd39 |
15 | 3745aa6aa0 |
hex | 1f3424fe2f |
134018825775 has 24 divisors (see below), whose sum is σ = 222504925440. Its totient is φ = 71177631840.
The previous prime is 134018825761. The next prime is 134018825777. The reversal of 134018825775 is 577528810431.
It is not a de Polignac number, because 134018825775 - 218 = 134018563631 is a prime.
It is a super-2 number, since 2×1340188257752 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134018825777) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3720397 + ... + 3756246.
It is an arithmetic number, because the mean of its divisors is an integer number (9271038560).
Almost surely, 2134018825775 is an apocalyptic number.
134018825775 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
134018825775 is a deficient number, since it is larger than the sum of its proper divisors (88486099665).
134018825775 is a wasteful number, since it uses less digits than its factorization.
134018825775 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7476895 (or 7476890 counting only the distinct ones).
The product of its (nonzero) digits is 1881600, while the sum is 51.
The spelling of 134018825775 in words is "one hundred thirty-four billion, eighteen million, eight hundred twenty-five thousand, seven hundred seventy-five".
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