Base | Representation |
---|---|
bin | 111110011010000111… |
… | …0010001000000100101 |
3 | 110210221002112120110101 |
4 | 1330310032101000211 |
5 | 4143433124003333 |
6 | 141322404424101 |
7 | 12453100255216 |
oct | 1746416210045 |
9 | 423832476411 |
10 | 134020141093 |
11 | 5192396a693 |
12 | 21b830a8031 |
13 | c83aa28947 |
14 | 66b538340d |
15 | 3745c6667d |
hex | 1f34391025 |
134020141093 has 2 divisors, whose sum is σ = 134020141094. Its totient is φ = 134020141092.
The previous prime is 134020141069. The next prime is 134020141097. The reversal of 134020141093 is 390141020431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 130669236324 + 3350904769 = 361482^2 + 57887^2 .
It is a cyclic number.
It is not a de Polignac number, because 134020141093 - 29 = 134020140581 is a prime.
It is a super-2 number, since 2×1340201410932 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134020141097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67010070546 + 67010070547.
It is an arithmetic number, because the mean of its divisors is an integer number (67010070547).
Almost surely, 2134020141093 is an apocalyptic number.
It is an amenable number.
134020141093 is a deficient number, since it is larger than the sum of its proper divisors (1).
134020141093 is an equidigital number, since it uses as much as digits as its factorization.
134020141093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 28.
The spelling of 134020141093 in words is "one hundred thirty-four billion, twenty million, one hundred forty-one thousand, ninety-three".
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