Base | Representation |
---|---|
bin | 111110011010000111… |
… | …0010001000001100111 |
3 | 110210221002112120112211 |
4 | 1330310032101001213 |
5 | 4143433124004114 |
6 | 141322404424251 |
7 | 12453100255342 |
oct | 1746416210147 |
9 | 423832476484 |
10 | 134020141159 |
11 | 5192396a743 |
12 | 21b830a8087 |
13 | c83aa28998 |
14 | 66b5383459 |
15 | 3745c666c4 |
hex | 1f34391067 |
134020141159 has 2 divisors, whose sum is σ = 134020141160. Its totient is φ = 134020141158.
The previous prime is 134020141097. The next prime is 134020141183. The reversal of 134020141159 is 951141020431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134020141159 - 217 = 134020010087 is a prime.
It is a super-2 number, since 2×1340201411592 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 134020141159.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134020141459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67010070579 + 67010070580.
It is an arithmetic number, because the mean of its divisors is an integer number (67010070580).
Almost surely, 2134020141159 is an apocalyptic number.
134020141159 is a deficient number, since it is larger than the sum of its proper divisors (1).
134020141159 is an equidigital number, since it uses as much as digits as its factorization.
134020141159 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 31.
The spelling of 134020141159 in words is "one hundred thirty-four billion, twenty million, one hundred forty-one thousand, one hundred fifty-nine".
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