Base | Representation |
---|---|
bin | 111110011010000111… |
… | …0010001101110100011 |
3 | 110210221002112201111100 |
4 | 1330310032101232203 |
5 | 4143433124102120 |
6 | 141322404445443 |
7 | 12453100266621 |
oct | 1746416215643 |
9 | 423832481440 |
10 | 134020144035 |
11 | 51923971918 |
12 | 21b830a9883 |
13 | c83aa2a09b |
14 | 66b5384511 |
15 | 3745c67490 |
hex | 1f34391ba3 |
134020144035 has 96 divisors (see below), whose sum is σ = 245365848000. Its totient is φ = 67594272768.
The previous prime is 134020144003. The next prime is 134020144117. The reversal of 134020144035 is 530441020431.
It is a happy number.
134020144035 is a `hidden beast` number, since 13 + 4 + 0 + 201 + 440 + 3 + 5 = 666.
It is not a de Polignac number, because 134020144035 - 25 = 134020144003 is a prime.
It is a super-2 number, since 2×1340201440352 (a number of 23 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 8735251 + ... + 8750579.
It is an arithmetic number, because the mean of its divisors is an integer number (2555894250).
Almost surely, 2134020144035 is an apocalyptic number.
134020144035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
134020144035 is a deficient number, since it is larger than the sum of its proper divisors (111345703965).
134020144035 is a wasteful number, since it uses less digits than its factorization.
134020144035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15525 (or 15522 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 27.
Adding to 134020144035 its reverse (530441020431), we get a palindrome (664461164466).
The spelling of 134020144035 in words is "one hundred thirty-four billion, twenty million, one hundred forty-four thousand, thirty-five".
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