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134020221 = 344673407
BaseRepresentation
bin1111111110011…
…11110001111101
3100100011221011220
413333033301331
5233302121341
621144303553
73215103336
oct777176175
9310157156
10134020221
1169718415
1238a71bb9
13219c560a
1413b2928d
15bb74a66
hex7fcfc7d

134020221 has 4 divisors (see below), whose sum is σ = 178693632. Its totient is φ = 89346812.

The previous prime is 134020219. The next prime is 134020247. The reversal of 134020221 is 122020431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 134020221 - 21 = 134020219 is a prime.

It is a super-2 number, since 2×1340202212 = 35922839273777682, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 134020221.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134000221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22336701 + ... + 22336706.

It is an arithmetic number, because the mean of its divisors is an integer number (44673408).

Almost surely, 2134020221 is an apocalyptic number.

It is an amenable number.

134020221 is a deficient number, since it is larger than the sum of its proper divisors (44673411).

134020221 is an equidigital number, since it uses as much as digits as its factorization.

134020221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44673410.

The product of its (nonzero) digits is 96, while the sum is 15.

The square root of 134020221 is about 11576.7102840142. The cubic root of 134020221 is about 511.7487335724.

Adding to 134020221 its reverse (122020431), we get a palindrome (256040652).

The spelling of 134020221 in words is "one hundred thirty-four million, twenty thousand, two hundred twenty-one".

Divisors: 1 3 44673407 134020221