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134020247 is a prime number
BaseRepresentation
bin1111111110011…
…11110010010111
3100100011221012212
413333033302113
5233302121442
621144304035
73215103404
oct777176227
9310157185
10134020247
1169718439
1238a7201b
13219c562a
1413b292ab
15bb74a82
hex7fcfc97

134020247 has 2 divisors, whose sum is σ = 134020248. Its totient is φ = 134020246.

The previous prime is 134020219. The next prime is 134020279. The reversal of 134020247 is 742020431.

It is a weak prime.

It is an emirp because it is prime and its reverse (742020431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134020247 is a prime.

It is a super-2 number, since 2×1340202472 = 35922853211882018, which contains 22 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134020217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67010123 + 67010124.

It is an arithmetic number, because the mean of its divisors is an integer number (67010124).

Almost surely, 2134020247 is an apocalyptic number.

134020247 is a deficient number, since it is larger than the sum of its proper divisors (1).

134020247 is an equidigital number, since it uses as much as digits as its factorization.

134020247 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1344, while the sum is 23.

The square root of 134020247 is about 11576.7114069584. The cubic root of 134020247 is about 511.7487666655.

Adding to 134020247 its reverse (742020431), we get a palindrome (876040678).

The spelling of 134020247 in words is "one hundred thirty-four million, twenty thousand, two hundred forty-seven".