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134020520013 = 32311333715099
BaseRepresentation
bin111110011010000111…
…1101101100001001101
3110210221010020211020110
41330310033231201031
54143433223120023
6141322420510233
712453103424022
oct1746417554115
9423833224213
10134020520013
11519240a9346
1221b8324b379
13c83ab2c263
1466b5441549
153745cdda93
hex1f343ed84d

134020520013 has 32 divisors (see below), whose sum is σ = 188206156800. Its totient is φ = 84664321280.

The previous prime is 134020519957. The next prime is 134020520057. The reversal of 134020520013 is 310025020431.

It is a cyclic number.

It is not a de Polignac number, because 134020520013 - 217 = 134020388941 is a prime.

It is a super-2 number, since 2×1340205200132 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134020520713) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 26281138 + ... + 26286236.

It is an arithmetic number, because the mean of its divisors is an integer number (5881442400).

Almost surely, 2134020520013 is an apocalyptic number.

It is an amenable number.

134020520013 is a deficient number, since it is larger than the sum of its proper divisors (54185636787).

134020520013 is a wasteful number, since it uses less digits than its factorization.

134020520013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8609.

The product of its (nonzero) digits is 720, while the sum is 21.

Adding to 134020520013 its reverse (310025020431), we get a palindrome (444045540444).

The spelling of 134020520013 in words is "one hundred thirty-four billion, twenty million, five hundred twenty thousand, thirteen".

Divisors: 1 3 23 69 113 339 2599 3371 5099 7797 10113 15297 77533 117277 232599 351831 380923 576187 1142769 1728561 8761229 13252301 17188729 26283687 39756903 51566187 395340767 1186022301 1942326377 5826979131 44673506671 134020520013