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13402191104609 is a prime number
BaseRepresentation
bin1100001100000111000011…
…0101110000101001100001
31202110020101202000112201212
43003001300311300221201
53224040141410321414
644300514231435505
72552163534522446
oct303016065605141
952406352015655
1013402191104609
1142a792353644a
121605526825b95
13762a8a232258
143449531cb9cd
1518394d5e183e
hexc3070d70a61

13402191104609 has 2 divisors, whose sum is σ = 13402191104610. Its totient is φ = 13402191104608.

The previous prime is 13402191104569. The next prime is 13402191104647. The reversal of 13402191104609 is 90640119120431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13274159530384 + 128031574225 = 3643372^2 + 357815^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13402191104609 is a prime.

It is not a weakly prime, because it can be changed into another prime (13402191100609) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701095552304 + 6701095552305.

It is an arithmetic number, because the mean of its divisors is an integer number (6701095552305).

Almost surely, 213402191104609 is an apocalyptic number.

It is an amenable number.

13402191104609 is a deficient number, since it is larger than the sum of its proper divisors (1).

13402191104609 is an equidigital number, since it uses as much as digits as its factorization.

13402191104609 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46656, while the sum is 41.

The spelling of 13402191104609 in words is "thirteen trillion, four hundred two billion, one hundred ninety-one million, one hundred four thousand, six hundred nine".