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13402191104647 is a prime number
BaseRepresentation
bin1100001100000111000011…
…0101110000101010000111
31202110020101202000112210021
43003001300311300222013
53224040141410322042
644300514231440011
72552163534522532
oct303016065605207
952406352015707
1013402191104647
1142a7923536484
121605526826007
13762a8a232287
143449531cba19
1518394d5e1867
hexc3070d70a87

13402191104647 has 2 divisors, whose sum is σ = 13402191104648. Its totient is φ = 13402191104646.

The previous prime is 13402191104609. The next prime is 13402191104677. The reversal of 13402191104647 is 74640119120431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13402191104647 - 215 = 13402191071879 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13402191104677) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701095552323 + 6701095552324.

It is an arithmetic number, because the mean of its divisors is an integer number (6701095552324).

Almost surely, 213402191104647 is an apocalyptic number.

13402191104647 is a deficient number, since it is larger than the sum of its proper divisors (1).

13402191104647 is an equidigital number, since it uses as much as digits as its factorization.

13402191104647 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 145152, while the sum is 43.

The spelling of 13402191104647 in words is "thirteen trillion, four hundred two billion, one hundred ninety-one million, one hundred four thousand, six hundred forty-seven".