1340222012993 has 2 divisors, whose sum is σ = 1340222012994. Its totient is φ = 1340222012992.

The previous prime is 1340222012971. The next prime is 1340222012999. The reversal of 1340222012993 is 3992102220431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1318861605889 + 21360407104 = 1148417^2 + 146152^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340222012993 - 2³⁰ = 1339148271169 is a prime.

It is a super-2 number, since 2×1340222012993² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1340222012999) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670111006496 + 670111006497.

It is an arithmetic number, because the mean of its divisors is an integer number (670111006497).

Almost surely, 2^{1340222012993} is an apocalyptic number.

It is an amenable number.

1340222012993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340222012993 is an equidigital number, since it uses as much as digits as its factorization.

1340222012993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46656, while the sum is 38.

The spelling of 1340222012993 in words is "one trillion, three hundred forty billion, two hundred twenty-two million, twelve thousand, nine hundred ninety-three".