134022214123542 has 48 divisors (see below), whose sum is σ = 307494985674240. Its totient is φ = 42041773314816.

The previous prime is 134022214123541. The next prime is 134022214123619. The reversal of 134022214123542 is 245321412220431.

134022214123542 is a `hidden beast` number, since 1 + 3 + 40 + 2 + 221 + 41 + 2 + 354 + 2 = 666.

It is a super-4 number, since 4×134022214123542⁴ (a number of 58 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 134022214123497 and 134022214123506.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134022214123541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 20054742 + ... + 25888937.

It is an arithmetic number, because the mean of its divisors is an integer number (6406145534880).

Almost surely, 2^{134022214123542} is an apocalyptic number.

134022214123542 is an abundant number, since it is smaller than the sum of its proper divisors (173472771550698).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134022214123542 is a wasteful number, since it uses less digits than its factorization.

134022214123542 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45953237 (or 45953234 counting only the distinct ones).

The product of its (nonzero) digits is 92160, while the sum is 36.

Adding to 134022214123542 its reverse (245321412220431), we get a palindrome (379343626343973).

The spelling of 134022214123542 in words is "one hundred thirty-four trillion, twenty-two billion, two hundred fourteen million, one hundred twenty-three thousand, five hundred forty-two".