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13402249841 is a prime number
BaseRepresentation
bin11000111101101011…
…00001101001110001
31021121000200211111202
430132311201221301
5204421433443331
610053520420545
7653056146461
oct143665415161
937530624452
1013402249841
115758247742
122720477755
131357820366
14911d57ba1
1553690becb
hex31ed61a71

13402249841 has 2 divisors, whose sum is σ = 13402249842. Its totient is φ = 13402249840.

The previous prime is 13402249807. The next prime is 13402249943. The reversal of 13402249841 is 14894220431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12498345616 + 903904225 = 111796^2 + 30065^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13402249841 is a prime.

It is a super-5 number, since 5×134022498415 (a number of 52 digits) contains 55555 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13402249795 and 13402249804.

It is not a weakly prime, because it can be changed into another prime (13402249741) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701124920 + 6701124921.

It is an arithmetic number, because the mean of its divisors is an integer number (6701124921).

Almost surely, 213402249841 is an apocalyptic number.

It is an amenable number.

13402249841 is a deficient number, since it is larger than the sum of its proper divisors (1).

13402249841 is an equidigital number, since it uses as much as digits as its factorization.

13402249841 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 55296, while the sum is 38.

The spelling of 13402249841 in words is "thirteen billion, four hundred two million, two hundred forty-nine thousand, eight hundred forty-one".