Base | Representation |
---|---|
bin | 11110011110010010001110… |
… | …100011101000100010100011 |
3 | 122120112102122000210011100102 |
4 | 132132102032203220202203 |
5 | 120031311141102211042 |
6 | 1153013035434413015 |
7 | 40141544520635135 |
oct | 3636221643504243 |
9 | 576472560704312 |
10 | 134022551210147 |
11 | 39781710219856 |
12 | 1304657529116b |
13 | 59a2370477b42 |
14 | 2514a24565055 |
15 | 107637a263b32 |
hex | 79e48e8e88a3 |
134022551210147 has 2 divisors, whose sum is σ = 134022551210148. Its totient is φ = 134022551210146.
The previous prime is 134022551210071. The next prime is 134022551210159. The reversal of 134022551210147 is 741012155220431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134022551210147 - 220 = 134022550161571 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 134022551210147.
It is not a weakly prime, because it can be changed into another prime (134022551213147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67011275605073 + 67011275605074.
It is an arithmetic number, because the mean of its divisors is an integer number (67011275605074).
Almost surely, 2134022551210147 is an apocalyptic number.
134022551210147 is a deficient number, since it is larger than the sum of its proper divisors (1).
134022551210147 is an equidigital number, since it uses as much as digits as its factorization.
134022551210147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 67200, while the sum is 38.
The spelling of 134022551210147 in words is "one hundred thirty-four trillion, twenty-two billion, five hundred fifty-one million, two hundred ten thousand, one hundred forty-seven".
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