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134022551210147 is a prime number
BaseRepresentation
bin11110011110010010001110…
…100011101000100010100011
3122120112102122000210011100102
4132132102032203220202203
5120031311141102211042
61153013035434413015
740141544520635135
oct3636221643504243
9576472560704312
10134022551210147
1139781710219856
121304657529116b
1359a2370477b42
142514a24565055
15107637a263b32
hex79e48e8e88a3

134022551210147 has 2 divisors, whose sum is σ = 134022551210148. Its totient is φ = 134022551210146.

The previous prime is 134022551210071. The next prime is 134022551210159. The reversal of 134022551210147 is 741012155220431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 134022551210147 - 220 = 134022550161571 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 134022551210147.

It is not a weakly prime, because it can be changed into another prime (134022551213147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67011275605073 + 67011275605074.

It is an arithmetic number, because the mean of its divisors is an integer number (67011275605074).

Almost surely, 2134022551210147 is an apocalyptic number.

134022551210147 is a deficient number, since it is larger than the sum of its proper divisors (1).

134022551210147 is an equidigital number, since it uses as much as digits as its factorization.

134022551210147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 67200, while the sum is 38.

The spelling of 134022551210147 in words is "one hundred thirty-four trillion, twenty-two billion, five hundred fifty-one million, two hundred ten thousand, one hundred forty-seven".