Base | Representation |
---|---|
bin | 11000111101101011… |
… | …10011101001001101 |
3 | 1021121000211120121002 |
4 | 30132311303221031 |
5 | 204421443323113 |
6 | 10053522150045 |
7 | 653056604354 |
oct | 143665635115 |
9 | 37530746532 |
10 | 13402323533 |
11 | 5758298045 |
12 | 27204b2325 |
13 | 1357847a71 |
14 | 911d7699b |
15 | 536923c58 |
hex | 31ed73a4d |
13402323533 has 2 divisors, whose sum is σ = 13402323534. Its totient is φ = 13402323532.
The previous prime is 13402323509. The next prime is 13402323547. The reversal of 13402323533 is 33532320431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6724492009 + 6677831524 = 82003^2 + 81718^2 .
It is a cyclic number.
It is not a de Polignac number, because 13402323533 - 216 = 13402257997 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13402323496 and 13402323505.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13402353533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701161766 + 6701161767.
It is an arithmetic number, because the mean of its divisors is an integer number (6701161767).
Almost surely, 213402323533 is an apocalyptic number.
It is an amenable number.
13402323533 is a deficient number, since it is larger than the sum of its proper divisors (1).
13402323533 is an equidigital number, since it uses as much as digits as its factorization.
13402323533 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19440, while the sum is 29.
Adding to 13402323533 its reverse (33532320431), we get a palindrome (46934643964).
The spelling of 13402323533 in words is "thirteen billion, four hundred two million, three hundred twenty-three thousand, five hundred thirty-three".
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