1340234115231 has 16 divisors (see below), whose sum is σ = 1990908707328. Its totient is φ = 794980905600.

The previous prime is 1340234115149. The next prime is 1340234115251. The reversal of 1340234115231 is 1325114320431.

It is not a de Polignac number, because 1340234115231 - 2¹³ = 1340234107039 is a prime.

It is a super-2 number, since 2×1340234115231² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340234115251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 432053290 + ... + 432056391.

It is an arithmetic number, because the mean of its divisors is an integer number (124431794208).

Almost surely, 2^{1340234115231} is an apocalyptic number.

1340234115231 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1340234115231 is a deficient number, since it is larger than the sum of its proper divisors (650674592097).

1340234115231 is a wasteful number, since it uses less digits than its factorization.

1340234115231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 864109742.

The product of its (nonzero) digits is 8640, while the sum is 30.

Adding to 1340234115231 its reverse (1325114320431), we get a palindrome (2665348435662).

The spelling of 1340234115231 in words is "one trillion, three hundred forty billion, two hundred thirty-four million, one hundred fifteen thousand, two hundred thirty-one".