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1340239004861 is a prime number
BaseRepresentation
bin10011100000001100011…
…110000100010010111101
311202010101120010200202112
4103200030132010102331
5133424302141123421
62503410341103405
7165554241401351
oct23401436042275
94663346120675
101340239004861
11477434a84109
121978b73b7b65
13994cb83c8a3
1448c217ad461
1524ce18bd45b
hex1380c7844bd

1340239004861 has 2 divisors, whose sum is σ = 1340239004862. Its totient is φ = 1340239004860.

The previous prime is 1340239004851. The next prime is 1340239004869. The reversal of 1340239004861 is 1684009320431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1303465189636 + 36773815225 = 1141694^2 + 191765^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1340239004861 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340239004869) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670119502430 + 670119502431.

It is an arithmetic number, because the mean of its divisors is an integer number (670119502431).

Almost surely, 21340239004861 is an apocalyptic number.

It is an amenable number.

1340239004861 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340239004861 is an equidigital number, since it uses as much as digits as its factorization.

1340239004861 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 124416, while the sum is 41.

The spelling of 1340239004861 in words is "one trillion, three hundred forty billion, two hundred thirty-nine million, four thousand, eight hundred sixty-one".