1340240100373 has 2 divisors, whose sum is σ = 1340240100374. Its totient is φ = 1340240100372.

The previous prime is 1340240100299. The next prime is 1340240100427. The reversal of 1340240100373 is 3730010420431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 760117191409 + 580122908964 = 871847^2 + 761658^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340240100373 - 2¹³ = 1340240092181 is a prime.

It is a super-2 number, since 2×1340240100373² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340240200373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670120050186 + 670120050187.

It is an arithmetic number, because the mean of its divisors is an integer number (670120050187).

Almost surely, 2^{1340240100373} is an apocalyptic number.

It is an amenable number.

1340240100373 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340240100373 is an equidigital number, since it uses as much as digits as its factorization.

1340240100373 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 28.

The spelling of 1340240100373 in words is "one trillion, three hundred forty billion, two hundred forty million, one hundred thousand, three hundred seventy-three".