1340241102001 has 2 divisors, whose sum is σ = 1340241102002. Its totient is φ = 1340241102000.

The previous prime is 1340241101999. The next prime is 1340241102029. The reversal of 1340241102001 is 1002011420431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1326505027600 + 13736074401 = 1151740^2 + 117201^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340241102001 - 2¹ = 1340241101999 is a prime.

It is a super-2 number, since 2×1340241102001² (a number of 25 digits) contains 22 as substring.

Together with 1340241101999, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 1340241102001.

It is not a weakly prime, because it can be changed into another prime (1340241102041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670120551000 + 670120551001.

It is an arithmetic number, because the mean of its divisors is an integer number (670120551001).

Almost surely, 2^{1340241102001} is an apocalyptic number.

It is an amenable number.

1340241102001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340241102001 is an equidigital number, since it uses as much as digits as its factorization.

1340241102001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 1340241102001 its reverse (1002011420431), we get a palindrome (2342252522432).

The spelling of 1340241102001 in words is "one trillion, three hundred forty billion, two hundred forty-one million, one hundred two thousand, one".