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134024111212012 = 2276771441423887
BaseRepresentation
bin11110011110010011101011…
…100010100100010111101100
3122120112120122202012110121021
4132132103223202210113230
5120031322334432241022
61153013454322543524
740141631262505420
oct3636235342442754
9576476582173537
10134024111212012
113978234086129a
121304692b807ba4
1359a255b717b78
142514b31806b80
15107641c1b17c7
hex79e4eb8a45ec

134024111212012 has 24 divisors (see below), whose sum is σ = 272048942165504. Its totient is φ = 56581607717712.

The previous prime is 134024111211997. The next prime is 134024111212063. The reversal of 134024111212012 is 210212111420431.

It is a super-2 number, since 2×1340241112120122 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35720710068 + ... + 35720713819.

Almost surely, 2134024111212012 is an apocalyptic number.

It is an amenable number.

134024111212012 is an abundant number, since it is smaller than the sum of its proper divisors (138024830953492).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134024111212012 is a wasteful number, since it uses less digits than its factorization.

134024111212012 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 71441423965 (or 71441423963 counting only the distinct ones).

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 134024111212012 its reverse (210212111420431), we get a palindrome (344236222632443).

The spelling of 134024111212012 in words is "one hundred thirty-four trillion, twenty-four billion, one hundred eleven million, two hundred twelve thousand, twelve".

Divisors: 1 2 4 7 14 28 67 134 268 469 938 1876 71441423887 142882847774 285765695548 500089967209 1000179934418 2000359868836 4786575400429 9573150800858 19146301601716 33506027803003 67012055606006 134024111212012