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13402423 is a prime number
BaseRepresentation
bin110011001000…
…000100110111
3221012220200001
4303020010313
511412334143
61155132131
7221630056
oct63100467
927186601
1013402423
117624491
1245a4047
132a13438
141acc39d
15129b14d
hexcc8137

13402423 has 2 divisors, whose sum is σ = 13402424. Its totient is φ = 13402422.

The previous prime is 13402373. The next prime is 13402427. The reversal of 13402423 is 32420431.

It is a strong prime.

It is an emirp because it is prime and its reverse (32420431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13402423 - 217 = 13271351 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13402423.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13402427) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701211 + 6701212.

It is an arithmetic number, because the mean of its divisors is an integer number (6701212).

Almost surely, 213402423 is an apocalyptic number.

13402423 is a deficient number, since it is larger than the sum of its proper divisors (1).

13402423 is an equidigital number, since it uses as much as digits as its factorization.

13402423 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 19.

The square root of 13402423 is about 3660.9319851644. The cubic root of 13402423 is about 237.5350891830.

Adding to 13402423 its reverse (32420431), we get a palindrome (45822854).

The spelling of 13402423 in words is "thirteen million, four hundred two thousand, four hundred twenty-three".