Base | Representation |
---|---|
bin | 10011100000001100110… |
… | …001100110001001010011 |
3 | 11202010101220202210020021 |
4 | 103200030301212021103 |
5 | 133424304443433433 |
6 | 2503411042524311 |
7 | 165554333042563 |
oct | 23401461461123 |
9 | 4663356683207 |
10 | 1340244124243 |
11 | 477437960402 |
12 | 1978b9066697 |
13 | 994cc912acb |
14 | 48c22342da3 |
15 | 24ce208022d |
hex | 1380cc66253 |
1340244124243 has 2 divisors, whose sum is σ = 1340244124244. Its totient is φ = 1340244124242.
The previous prime is 1340244124231. The next prime is 1340244124259. The reversal of 1340244124243 is 3424214420431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1340244124243 - 217 = 1340243993171 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1340244124199 and 1340244124208.
It is not a weakly prime, because it can be changed into another prime (1340244121243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670122062121 + 670122062122.
It is an arithmetic number, because the mean of its divisors is an integer number (670122062122).
Almost surely, 21340244124243 is an apocalyptic number.
1340244124243 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340244124243 is an equidigital number, since it uses as much as digits as its factorization.
1340244124243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 73728, while the sum is 34.
Adding to 1340244124243 its reverse (3424214420431), we get a palindrome (4764458544674).
The spelling of 1340244124243 in words is "one trillion, three hundred forty billion, two hundred forty-four million, one hundred twenty-four thousand, two hundred forty-three".
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