134025130471 has 2 divisors, whose sum is σ = 134025130472. Its totient is φ = 134025130470.

The previous prime is 134025130453. The next prime is 134025130483. The reversal of 134025130471 is 174031520431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 134025130471 - 2¹³ = 134025122279 is a prime.

It is a super-3 number, since 3×134025130471³ (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134025130411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67012565235 + 67012565236.

It is an arithmetic number, because the mean of its divisors is an integer number (67012565236).

Almost surely, 2^134025130471 is an apocalyptic number.

134025130471 is a deficient number, since it is larger than the sum of its proper divisors (1).

134025130471 is an equidigital number, since it uses as much as digits as its factorization.

134025130471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10080, while the sum is 31.

The spelling of 134025130471 in words is "one hundred thirty-four billion, twenty-five million, one hundred thirty thousand, four hundred seventy-one".