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13402516529 is a prime number
BaseRepresentation
bin11000111101101101…
…00010110000110001
31021121001012101100002
430132312202300301
5204422021012104
610053530235345
7653061340133
oct143666426061
937531171302
1013402516529
11575840a046
122720585b55
1313578b486c
14911dc7053
1553696101e
hex31eda2c31

13402516529 has 2 divisors, whose sum is σ = 13402516530. Its totient is φ = 13402516528.

The previous prime is 13402516511. The next prime is 13402516537. The reversal of 13402516529 is 92561520431.

13402516529 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7562041600 + 5840474929 = 86960^2 + 76423^2 .

It is an emirp because it is prime and its reverse (92561520431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13402516529 - 28 = 13402516273 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13402516492 and 13402516501.

It is not a weakly prime, because it can be changed into another prime (13402516579) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701258264 + 6701258265.

It is an arithmetic number, because the mean of its divisors is an integer number (6701258265).

Almost surely, 213402516529 is an apocalyptic number.

It is an amenable number.

13402516529 is a deficient number, since it is larger than the sum of its proper divisors (1).

13402516529 is an equidigital number, since it uses as much as digits as its factorization.

13402516529 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64800, while the sum is 38.

The spelling of 13402516529 in words is "thirteen billion, four hundred two million, five hundred sixteen thousand, five hundred twenty-nine".