Base | Representation |
---|---|
bin | 111110011010010000… |
… | …1100001100001011101 |
3 | 110210221110001001112021 |
4 | 1330310201201201131 |
5 | 4143440422030334 |
6 | 141323104540141 |
7 | 12453161212423 |
oct | 1746441414135 |
9 | 423843031467 |
10 | 134025189469 |
11 | 519267a85a6 |
12 | 21b84921651 |
13 | c83baa5752 |
14 | 66b5cd9113 |
15 | 37464123b4 |
hex | 1f3486185d |
134025189469 has 2 divisors, whose sum is σ = 134025189470. Its totient is φ = 134025189468.
The previous prime is 134025189421. The next prime is 134025189497. The reversal of 134025189469 is 964981520431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 85608908100 + 48416281369 = 292590^2 + 220037^2 .
It is a cyclic number.
It is not a de Polignac number, because 134025189469 - 223 = 134016800861 is a prime.
It is a super-2 number, since 2×1340251894692 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134025189409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67012594734 + 67012594735.
It is an arithmetic number, because the mean of its divisors is an integer number (67012594735).
Almost surely, 2134025189469 is an apocalyptic number.
It is an amenable number.
134025189469 is a deficient number, since it is larger than the sum of its proper divisors (1).
134025189469 is an equidigital number, since it uses as much as digits as its factorization.
134025189469 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1866240, while the sum is 52.
The spelling of 134025189469 in words is "one hundred thirty-four billion, twenty-five million, one hundred eighty-nine thousand, four hundred sixty-nine".
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