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134025189469 is a prime number
BaseRepresentation
bin111110011010010000…
…1100001100001011101
3110210221110001001112021
41330310201201201131
54143440422030334
6141323104540141
712453161212423
oct1746441414135
9423843031467
10134025189469
11519267a85a6
1221b84921651
13c83baa5752
1466b5cd9113
1537464123b4
hex1f3486185d

134025189469 has 2 divisors, whose sum is σ = 134025189470. Its totient is φ = 134025189468.

The previous prime is 134025189421. The next prime is 134025189497. The reversal of 134025189469 is 964981520431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 85608908100 + 48416281369 = 292590^2 + 220037^2 .

It is a cyclic number.

It is not a de Polignac number, because 134025189469 - 223 = 134016800861 is a prime.

It is a super-2 number, since 2×1340251894692 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134025189409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67012594734 + 67012594735.

It is an arithmetic number, because the mean of its divisors is an integer number (67012594735).

Almost surely, 2134025189469 is an apocalyptic number.

It is an amenable number.

134025189469 is a deficient number, since it is larger than the sum of its proper divisors (1).

134025189469 is an equidigital number, since it uses as much as digits as its factorization.

134025189469 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1866240, while the sum is 52.

The spelling of 134025189469 in words is "one hundred thirty-four billion, twenty-five million, one hundred eighty-nine thousand, four hundred sixty-nine".