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1340252531 is a prime number
BaseRepresentation
bin100111111100010…
…1010000101110011
310110101220212211122
41033320222011303
510221101040111
6340554132455
745132646532
oct11770520563
93411825748
101340252531
116285a0622
12314a2112b
1318488c747
14c9ddc319
157c9e1cdb
hex4fe2a173

1340252531 has 2 divisors, whose sum is σ = 1340252532. Its totient is φ = 1340252530.

The previous prime is 1340252497. The next prime is 1340252549. The reversal of 1340252531 is 1352520431.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1340252531 - 230 = 266510707 is a prime.

It is a super-2 number, since 2×13402525312 = 3592553693703811922, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1340252531.

It is not a weakly prime, because it can be changed into another prime (1340252561) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670126265 + 670126266.

It is an arithmetic number, because the mean of its divisors is an integer number (670126266).

Almost surely, 21340252531 is an apocalyptic number.

1340252531 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340252531 is an equidigital number, since it uses as much as digits as its factorization.

1340252531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3600, while the sum is 26.

The square root of 1340252531 is about 36609.4595835557. The cubic root of 1340252531 is about 1102.5430230210.

Adding to 1340252531 its reverse (1352520431), we get a palindrome (2692772962).

The spelling of 1340252531 in words is "one billion, three hundred forty million, two hundred fifty-two thousand, five hundred thirty-one".