Base | Representation |
---|---|
bin | 11000111101110001… |
… | …10000000010111111 |
3 | 1021121002021210011111 |
4 | 30132320300002333 |
5 | 204422143021411 |
6 | 10053550502451 |
7 | 653066300251 |
oct | 143670600277 |
9 | 37532253144 |
10 | 13403095231 |
11 | 5758774909 |
12 | 2720804a27 |
13 | 1357a580a6 |
14 | 9120d7cd1 |
15 | 536a27721 |
hex | 31ee300bf |
13403095231 has 2 divisors, whose sum is σ = 13403095232. Its totient is φ = 13403095230.
The previous prime is 13403095169. The next prime is 13403095249. The reversal of 13403095231 is 13259030431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13403095231 - 213 = 13403087039 is a prime.
It is a super-2 number, since 2×134030952312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13403095193 and 13403095202.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13403095261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701547615 + 6701547616.
It is an arithmetic number, because the mean of its divisors is an integer number (6701547616).
Almost surely, 213403095231 is an apocalyptic number.
13403095231 is a deficient number, since it is larger than the sum of its proper divisors (1).
13403095231 is an equidigital number, since it uses as much as digits as its factorization.
13403095231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 31.
The spelling of 13403095231 in words is "thirteen billion, four hundred three million, ninety-five thousand, two hundred thirty-one".
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