Base | Representation |
---|---|
bin | 10011100000010000101… |
… | …111110110100100000111 |
3 | 11202010120120012001100111 |
4 | 103200100233312210013 |
5 | 133424424024313241 |
6 | 2503421423253451 |
7 | 165556102423021 |
oct | 23402057664407 |
9 | 4663516161314 |
10 | 1340310776071 |
11 | 477471544963 |
12 | 19791744a287 |
13 | 9951067b667 |
14 | 48c2b133011 |
15 | 24ce7d48c81 |
hex | 13810bf6907 |
1340310776071 has 2 divisors, whose sum is σ = 1340310776072. Its totient is φ = 1340310776070.
The previous prime is 1340310776059. The next prime is 1340310776093. The reversal of 1340310776071 is 1706770130431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1340310776071 - 231 = 1338163292423 is a prime.
It is a super-3 number, since 3×13403107760713 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1340310776671) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670155388035 + 670155388036.
It is an arithmetic number, because the mean of its divisors is an integer number (670155388036).
Almost surely, 21340310776071 is an apocalyptic number.
1340310776071 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340310776071 is an equidigital number, since it uses as much as digits as its factorization.
1340310776071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 74088, while the sum is 40.
The spelling of 1340310776071 in words is "one trillion, three hundred forty billion, three hundred ten million, seven hundred seventy-six thousand, seventy-one".
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