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134031324330383 is a prime number
BaseRepresentation
bin11110011110011010011001…
…011110011011100110001111
3122120120021021102221211211112
4132132122121132123212033
5120031432123012033013
61153021050153042235
740142305110140144
oct3636323136334617
9576507242854745
10134031324330383
1139785402438947
12130482033b637b
1359a313ac1c14c
14251521779c3cb
1510766e0576ba8
hex79e69979b98f

134031324330383 has 2 divisors, whose sum is σ = 134031324330384. Its totient is φ = 134031324330382.

The previous prime is 134031324330341. The next prime is 134031324330401. The reversal of 134031324330383 is 383033423130431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 134031324330383 - 222 = 134031320136079 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 134031324330383.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134031324330313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67015662165191 + 67015662165192.

It is an arithmetic number, because the mean of its divisors is an integer number (67015662165192).

Almost surely, 2134031324330383 is an apocalyptic number.

134031324330383 is a deficient number, since it is larger than the sum of its proper divisors (1).

134031324330383 is an equidigital number, since it uses as much as digits as its factorization.

134031324330383 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 559872, while the sum is 41.

The spelling of 134031324330383 in words is "one hundred thirty-four trillion, thirty-one billion, three hundred twenty-four million, three hundred thirty thousand, three hundred eighty-three".