134032124011234 has 4 divisors (see below), whose sum is σ = 201048186016854. Its totient is φ = 67016062005616.

The previous prime is 134032124011231. The next prime is 134032124011301. The reversal of 134032124011234 is 432110421230431.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 118493130557025 + 15538993454209 = 10885455^2 + 3941953^2 .

It is a super-2 number, since 2×134032124011234² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 134032124011196 and 134032124011205.

It is not an unprimeable number, because it can be changed into a prime (134032124011231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33508031002807 + ... + 33508031002810.

Almost surely, 2^{134032124011234} is an apocalyptic number.

134032124011234 is a deficient number, since it is larger than the sum of its proper divisors (67016062005620).

134032124011234 is an equidigital number, since it uses as much as digits as its factorization.

134032124011234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67016062005619.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 134032124011234 its reverse (432110421230431), we get a palindrome (566142545241665).

The spelling of 134032124011234 in words is "one hundred thirty-four trillion, thirty-two billion, one hundred twenty-four million, eleven thousand, two hundred thirty-four".