13403213032003 has 2 divisors, whose sum is σ = 13403213032004. Its totient is φ = 13403213032002.

The previous prime is 13403213031997. The next prime is 13403213032021. The reversal of 13403213032003 is 30023031230431.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13403213032003 is a prime.

It is a super-3 number, since 3×13403213032003³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (13403213032073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701606516001 + 6701606516002.

It is an arithmetic number, because the mean of its divisors is an integer number (6701606516002).

Almost surely, 2^{13403213032003} is an apocalyptic number.

13403213032003 is a deficient number, since it is larger than the sum of its proper divisors (1).

13403213032003 is an equidigital number, since it uses as much as digits as its factorization.

13403213032003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 13403213032003 its reverse (30023031230431), we get a palindrome (43426244262434).

The spelling of 13403213032003 in words is "thirteen trillion, four hundred three billion, two hundred thirteen million, thirty-two thousand, three".