Base | Representation |
---|---|
bin | 11000111101110010… |
… | …10111001000111001 |
3 | 1021121002120220210221 |
4 | 30132321113020321 |
5 | 204422213132403 |
6 | 10053554140041 |
7 | 653100535135 |
oct | 143671271071 |
9 | 37532526727 |
10 | 13403255353 |
11 | 5758874144 |
12 | 2720881621 |
13 | 1357ab2c37 |
14 | 91213a3c5 |
15 | 536a59dbd |
hex | 31ee57239 |
13403255353 has 2 divisors, whose sum is σ = 13403255354. Its totient is φ = 13403255352.
The previous prime is 13403255297. The next prime is 13403255357. The reversal of 13403255353 is 35355230431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13268044969 + 135210384 = 115187^2 + 11628^2 .
It is a cyclic number.
It is not a de Polignac number, because 13403255353 - 213 = 13403247161 is a prime.
It is not a weakly prime, because it can be changed into another prime (13403255357) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701627676 + 6701627677.
It is an arithmetic number, because the mean of its divisors is an integer number (6701627677).
Almost surely, 213403255353 is an apocalyptic number.
It is an amenable number.
13403255353 is a deficient number, since it is larger than the sum of its proper divisors (1).
13403255353 is an equidigital number, since it uses as much as digits as its factorization.
13403255353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81000, while the sum is 34.
Adding to 13403255353 its reverse (35355230431), we get a palindrome (48758485784).
The spelling of 13403255353 in words is "thirteen billion, four hundred three million, two hundred fifty-five thousand, three hundred fifty-three".
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