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13403294897 is a prime number
BaseRepresentation
bin11000111101110011…
…00000110010110001
31021121002122221001112
430132321200302301
5204422220414042
610053555043105
7653101061336
oct143671406261
937532587045
1013403294897
1157588a0923
1227208a0495
131357ac7c35
1491214a98d
15536a66982
hex31ee60cb1

13403294897 has 2 divisors, whose sum is σ = 13403294898. Its totient is φ = 13403294896.

The previous prime is 13403294753. The next prime is 13403294899. The reversal of 13403294897 is 79849230431.

13403294897 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12635783281 + 767511616 = 112409^2 + 27704^2 .

It is a cyclic number.

It is not a de Polignac number, because 13403294897 - 212 = 13403290801 is a prime.

Together with 13403294899, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13403294899) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701647448 + 6701647449.

It is an arithmetic number, because the mean of its divisors is an integer number (6701647449).

Almost surely, 213403294897 is an apocalyptic number.

It is an amenable number.

13403294897 is a deficient number, since it is larger than the sum of its proper divisors (1).

13403294897 is an equidigital number, since it uses as much as digits as its factorization.

13403294897 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1306368, while the sum is 50.

The spelling of 13403294897 in words is "thirteen billion, four hundred three million, two hundred ninety-four thousand, eight hundred ninety-seven".