1340331111221 has 2 divisors, whose sum is σ = 1340331111222. Its totient is φ = 1340331111220.

The previous prime is 1340331111193. The next prime is 1340331111247. The reversal of 1340331111221 is 1221111330431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1303047363121 + 37283748100 = 1141511^2 + 193090^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340331111221 - 2³⁰ = 1339257369397 is a prime.

It is a super-2 number, since 2×1340331111221² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340331111421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670165555610 + 670165555611.

It is an arithmetic number, because the mean of its divisors is an integer number (670165555611).

Almost surely, 2^{1340331111221} is an apocalyptic number.

It is an amenable number.

1340331111221 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340331111221 is an equidigital number, since it uses as much as digits as its factorization.

1340331111221 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 1340331111221 its reverse (1221111330431), we get a palindrome (2561442441652).

The spelling of 1340331111221 in words is "one trillion, three hundred forty billion, three hundred thirty-one million, one hundred eleven thousand, two hundred twenty-one".