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1340336437481 is a prime number
BaseRepresentation
bin10011100000010010010…
…001101111100011101001
311202010122100110210012002
4103200102101233203221
5133430002111444411
62503424141300345
7165556533511436
oct23402221574351
94663570423162
101340336437481
11477484a81738
12197923b646b5
1399515a94922
1448c306d2b8d
1524cea21733b
hex1381246f8e9

1340336437481 has 2 divisors, whose sum is σ = 1340336437482. Its totient is φ = 1340336437480.

The previous prime is 1340336437459. The next prime is 1340336437487. The reversal of 1340336437481 is 1847346330431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1319089002256 + 21247435225 = 1148516^2 + 145765^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1340336437481 is a prime.

It is a super-2 number, since 2×13403364374812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1340336437487) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670168218740 + 670168218741.

It is an arithmetic number, because the mean of its divisors is an integer number (670168218741).

Almost surely, 21340336437481 is an apocalyptic number.

It is an amenable number.

1340336437481 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340336437481 is an equidigital number, since it uses as much as digits as its factorization.

1340336437481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1741824, while the sum is 47.

The spelling of 1340336437481 in words is "one trillion, three hundred forty billion, three hundred thirty-six million, four hundred thirty-seven thousand, four hundred eighty-one".