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13403412153 = 3217367238703
BaseRepresentation
bin11000111101110011…
…11101011010111001
31021121002212212220100
430132321331122321
5204422233142103
610054001350013
7653102060235
oct143671753271
937532785810
1013403412153
115758970a2a
122720938309
131357b39411
1491217b5c5
15536a8b5a3
hex31ee7d6b9

13403412153 has 24 divisors (see below), whose sum is σ = 20555278848. Its totient is φ = 8387033472.

The previous prime is 13403412133. The next prime is 13403412229. The reversal of 13403412153 is 35121430431.

It is a happy number.

13403412153 is a `hidden beast` number, since 1 + 3 + 403 + 41 + 215 + 3 = 666.

It is not a de Polignac number, because 13403412153 - 26 = 13403412089 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13403412133) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 63201 + ... + 175502.

It is an arithmetic number, because the mean of its divisors is an integer number (856469952).

Almost surely, 213403412153 is an apocalyptic number.

It is an amenable number.

13403412153 is a deficient number, since it is larger than the sum of its proper divisors (7151866695).

13403412153 is a wasteful number, since it uses less digits than its factorization.

13403412153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 239093 (or 239090 counting only the distinct ones).

The product of its (nonzero) digits is 4320, while the sum is 27.

Adding to 13403412153 its reverse (35121430431), we get a palindrome (48524842584).

The spelling of 13403412153 in words is "thirteen billion, four hundred three million, four hundred twelve thousand, one hundred fifty-three".

Divisors: 1 3 9 17 51 153 367 1101 3303 6239 18717 56151 238703 716109 2148327 4057951 12173853 36521559 87604001 262812003 788436009 1489268017 4467804051 13403412153