13403412133 has 2 divisors, whose sum is σ = 13403412134. Its totient is φ = 13403412132.

The previous prime is 13403412089. The next prime is 13403412229. The reversal of 13403412133 is 33121430431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10237999489 + 3165412644 = 101183^2 + 56262^2 .

It is an emirp because it is prime and its reverse (33121430431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13403412133 - 2¹³ = 13403403941 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13403412098 and 13403412107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13403416133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701706066 + 6701706067.

It is an arithmetic number, because the mean of its divisors is an integer number (6701706067).

Almost surely, 2^13403412133 is an apocalyptic number.

It is an amenable number.

13403412133 is a deficient number, since it is larger than the sum of its proper divisors (1).

13403412133 is an equidigital number, since it uses as much as digits as its factorization.

13403412133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13403412133 its reverse (33121430431), we get a palindrome (46524842564).

The spelling of 13403412133 in words is "thirteen billion, four hundred three million, four hundred twelve thousand, one hundred thirty-three".