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1340341403100 = 2235275981113339
BaseRepresentation
bin10011100000010010100…
…100101011110111011100
311202010122200211001201220
4103200102210223313130
5133430004344344400
62503424435533340
7165556623642450
oct23402244536734
94663580731656
101340341403100
11477487863457
1219792575a250
1399516b12b6b
1448c31226660
1524cea8987a0
hex1381292bddc

1340341403100 has 288 divisors, whose sum is σ = 4513077811200. Its totient is φ = 300777235200.

The previous prime is 1340341403081. The next prime is 1340341403111. The reversal of 1340341403100 is 13041430431.

It is a super-2 number, since 2×13403414031002 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 100476231 + ... + 100489569.

Almost surely, 21340341403100 is an apocalyptic number.

1340341403100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1340341403100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2256538905600).

1340341403100 is an abundant number, since it is smaller than the sum of its proper divisors (3172736408100).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1340341403100 is a wasteful number, since it uses less digits than its factorization.

1340341403100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14233 (or 14226 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 1340341403100 its reverse (13041430431), we get a palindrome (1353382833531).

The spelling of 1340341403100 in words is "one trillion, three hundred forty billion, three hundred forty-one million, four hundred three thousand, one hundred".