1340400040381 has 2 divisors, whose sum is σ = 1340400040382. Its totient is φ = 1340400040380.

The previous prime is 1340400040327. The next prime is 1340400040423. The reversal of 1340400040381 is 1830400040431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1018787422500 + 321612617881 = 1009350^2 + 567109^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1340400040381 is a prime.

It is a super-2 number, since 2×1340400040381² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340400040321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670200020190 + 670200020191.

It is an arithmetic number, because the mean of its divisors is an integer number (670200020191).

Almost surely, 2^{1340400040381} is an apocalyptic number.

It is an amenable number.

1340400040381 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340400040381 is an equidigital number, since it uses as much as digits as its factorization.

1340400040381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 28.

The spelling of 1340400040381 in words is "one trillion, three hundred forty billion, four hundred million, forty thousand, three hundred eighty-one".