1340400040531 has 2 divisors, whose sum is σ = 1340400040532. Its totient is φ = 1340400040530.

The previous prime is 1340400040517. The next prime is 1340400040579. The reversal of 1340400040531 is 1350400040431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1340400040531 - 2³³ = 1331810105939 is a prime.

It is a super-2 number, since 2×1340400040531² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1340400040496 and 1340400040505.

It is not a weakly prime, because it can be changed into another prime (1340400040591) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670200020265 + 670200020266.

It is an arithmetic number, because the mean of its divisors is an integer number (670200020266).

Almost surely, 2^{1340400040531} is an apocalyptic number.

1340400040531 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340400040531 is an equidigital number, since it uses as much as digits as its factorization.

1340400040531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 1340400040531 its reverse (1350400040431), we get a palindrome (2690800080962).

The spelling of 1340400040531 in words is "one trillion, three hundred forty billion, four hundred million, forty thousand, five hundred thirty-one".