Base | Representation |
---|---|
bin | 111110011010101101… |
… | …0011100011110110111 |
3 | 110210222111010011001201 |
4 | 1330311122130132313 |
5 | 4144003232023111 |
6 | 141324400433331 |
7 | 12453432100501 |
oct | 1746532343667 |
9 | 423874104051 |
10 | 134040111031 |
11 | 5193416a372 |
12 | 21b89918847 |
13 | c841bcb488 |
14 | 66b7ca0d71 |
15 | 37478ad6c1 |
hex | 1f3569c7b7 |
134040111031 has 2 divisors, whose sum is σ = 134040111032. Its totient is φ = 134040111030.
The previous prime is 134040110989. The next prime is 134040111061. The reversal of 134040111031 is 130111040431.
It is a strong prime.
It is an emirp because it is prime and its reverse (130111040431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134040111031 - 213 = 134040102839 is a prime.
It is a super-2 number, since 2×1340401110312 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134040111061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67020055515 + 67020055516.
It is an arithmetic number, because the mean of its divisors is an integer number (67020055516).
Almost surely, 2134040111031 is an apocalyptic number.
134040111031 is a deficient number, since it is larger than the sum of its proper divisors (1).
134040111031 is an equidigital number, since it uses as much as digits as its factorization.
134040111031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 134040111031 its reverse (130111040431), we get a palindrome (264151151462).
The spelling of 134040111031 in words is "one hundred thirty-four billion, forty million, one hundred eleven thousand, thirty-one".
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