13404021140 has 12 divisors (see below), whose sum is σ = 28148444436. Its totient is φ = 5361608448.

The previous prime is 13404021097. The next prime is 13404021157. The reversal of 13404021140 is 4112040431.

It can be written as a sum of positive squares in 2 ways, for example, as 9838259344 + 3565761796 = 99188^2 + 59714^2 .

It is a super-3 number, since 3×13404021140³ (a number of 31 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20), and also a Moran number because the ratio is a prime number: 670201057 = 13404021140 / (1 + 3 + 4 + 0 + 4 + 0 + 2 + 1 + 1 + 4 + 0).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335100509 + ... + 335100548.

It is an arithmetic number, because the mean of its divisors is an integer number (2345703703).

Almost surely, 2^13404021140 is an apocalyptic number.

13404021140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13404021140 is an abundant number, since it is smaller than the sum of its proper divisors (14744423296).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13404021140 is a wasteful number, since it uses less digits than its factorization.

13404021140 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 670201066 (or 670201064 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 13404021140 its reverse (4112040431), we get a palindrome (17516061571).

The spelling of 13404021140 in words is "thirteen billion, four hundred four million, twenty-one thousand, one hundred forty".